Whakaoti i te a^4-3a^2-2a=0

$$a ^ { 4 } - 3 a ^ { 2 } - 2 a = 0$$

Whakaoti mō a

$$a=2$$

$$a=0$$

$$a=-1$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Whakakapia te t mō te a^{2}.

$$t^{2}-3t-2=0$$

Ka taea ngā whārite katoa o te momo ax^{2}+bx+c=0 te whakaoti mā te ture pūrua: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Whakakapia te 1 mō te a, te -3 mō te b, me te -2 mō te c i te ture pūrua.

$$t=\frac{-\left(-3\right)±\sqrt{\left(-3\right)^{2}-4\times 1\left(-2\right)}}{2}$$

Mahia ngā tātaitai.

$$t=\frac{3±\sqrt{17}}{2}$$

Whakaotia te whārite t=\frac{3±\sqrt{17}}{2} ina he tōrunga te ±, ina he tōraro te ±.

$$t=\frac{\sqrt{17}+3}{2} t=\frac{3-\sqrt{17}}{2}$$

I te mea ko a=t^{2}, ka riro ngā otinga mā te arotake i te a=±\sqrt{t} mō t tōrunga.

$$a=\frac{\sqrt{2\sqrt{17}+6}}{2} a=-\frac{\sqrt{2\sqrt{17}+6}}{2}$$