Whakaoti i te a^2-1=0

$$a ^ { 2 } - 1 = 0$$

Whakaoti mō a

$$a=1$$

$$a=-1$$

Ngā Hipanga Whakamahi Rerekētanga o ngā Pūrua

Whakaarohia te a^{2}-1. Tuhia anō te a^{2}-1 hei a^{2}-1^{2}. Ka taea te rerekētanga o ngā pūrua te whakatauwehe mā te ture: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).

$$\left(a-1\right)\left(a+1\right)=0$$

Hei kimi otinga whārite, me whakaoti te a-1=0 me te a+1=0.

$$a=1 a=-1$$

Ngā Upane mā te Kimi Pūtakerua

Me tāpiri te 1 ki ngā taha e rua. Ko te tau i tāpiria he kore ka hua koia tonu.

$$a^{2}=1$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$a=1 a=-1$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Ko ngā tikanga tātai pūrua pēnei i tēnei nā, me te kīanga tau x^{2} engari kāore he kīanga tau x, ka taea tonu te whakaoti mā te whakamahi i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, ina tuhia ki te tānga ngahuru: ax^{2}+bx+c=0.

$$a^{2}-1=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me -1 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$a=\frac{0±\sqrt{0^{2}-4\left(-1\right)}}{2}$$

Pūrua 0.

$$a=\frac{0±\sqrt{-4\left(-1\right)}}{2}$$

Whakareatia -4 ki te -1.

$$a=\frac{0±\sqrt{4}}{2}$$

Tuhia te pūtakerua o te 4.

$$a=\frac{0±2}{2}$$

Nā, me whakaoti te whārite a=\frac{0±2}{2} ina he tāpiri te ±. Whakawehe 2 ki te 2.

$$a=1$$

Nā, me whakaoti te whārite a=\frac{0±2}{2} ina he tango te ±. Whakawehe -2 ki te 2.

$$a=-1$$

Kua oti te whārite te whakatau.

$$a=1 a=-1$$