Whakaoti i te a^2=7

$$a ^ { 2 } = 7$$

Whakaoti mō a

$$a=\sqrt{7}\approx 2.645751311$$

$$a=-\sqrt{7}\approx -2.645751311$$

Ngā Upane mā te Kimi Pūtakerua

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$a=\sqrt{7} a=-\sqrt{7}$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Tangohia te 7 mai i ngā taha e rua.

$$a^{2}-7=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me -7 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$a=\frac{0±\sqrt{0^{2}-4\left(-7\right)}}{2}$$

Pūrua 0.

$$a=\frac{0±\sqrt{-4\left(-7\right)}}{2}$$

Whakareatia -4 ki te -7.

$$a=\frac{0±\sqrt{28}}{2}$$

Tuhia te pūtakerua o te 28.

$$a=\frac{0±2\sqrt{7}}{2}$$

Nā, me whakaoti te whārite a=\frac{0±2\sqrt{7}}{2} ina he tāpiri te ±.

$$a=\sqrt{7}$$

Nā, me whakaoti te whārite a=\frac{0±2\sqrt{7}}{2} ina he tango te ±.

$$a=-\sqrt{7}$$

Kua oti te whārite te whakatau.

$$a=\sqrt{7} a=-\sqrt{7}$$