Whakaoti i te a^2=15^2-18^2

$$a ^ { 2 } = 15 ^ { 2 } - 18 ^ { 2 }$$

Whakaoti mō a

$$a=-3\sqrt{11}i\approx -0-9.949874371i$$

$$a=3\sqrt{11}i\approx 9.949874371i$$

Ngā Upane mā te Kimi Pūtakerua

Tātaihia te 15 mā te pū o 2, kia riro ko 225.

$$a^{2}=225-18^{2}$$

Tātaihia te 18 mā te pū o 2, kia riro ko 324.

$$a^{2}=225-324$$

Tangohia te 324 i te 225, ka -99.

$$a^{2}=-99$$

Kua oti te whārite te whakatau.

$$a=3\sqrt{11}i a=-3\sqrt{11}i$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Tātaihia te 15 mā te pū o 2, kia riro ko 225.

$$a^{2}=225-18^{2}$$

Tātaihia te 18 mā te pū o 2, kia riro ko 324.

$$a^{2}=225-324$$

Tangohia te 324 i te 225, ka -99.

$$a^{2}=-99$$

Me tāpiri te 99 ki ngā taha e rua.

$$a^{2}+99=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me 99 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$a=\frac{0±\sqrt{0^{2}-4\times 99}}{2}$$

Pūrua 0.

$$a=\frac{0±\sqrt{-4\times 99}}{2}$$

Whakareatia -4 ki te 99.

$$a=\frac{0±\sqrt{-396}}{2}$$

Tuhia te pūtakerua o te -396.

$$a=\frac{0±6\sqrt{11}i}{2}$$

Nā, me whakaoti te whārite a=\frac{0±6\sqrt{11}i}{2} ina he tāpiri te ±.

$$a=3\sqrt{11}i$$

Nā, me whakaoti te whārite a=\frac{0±6\sqrt{11}i}{2} ina he tango te ±.

$$a=-3\sqrt{11}i$$

Kua oti te whārite te whakatau.

$$a=3\sqrt{11}i a=-3\sqrt{11}i$$