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p+q=1 pq=1\left(-2\right)=-2
Whakatauwehea te kīanga mā te whakarōpū. Tuatahi, me tuhi anō te kīanga hei a^{2}+pa+qa-2. Hei kimi p me q, whakaritea tētahi pūnaha kia whakaoti.
p=-1 q=2
I te mea kua tōraro te pq, he tauaro ngā tohu o p me q. I te mea kua tōrunga te p+q, he nui ake te uara pū o te tau tōrunga i tō te tōraro. Ko te takirua anake pērā ko te otinga pūnaha.
\left(a^{2}-a\right)+\left(2a-2\right)
Tuhia anō te a^{2}+a-2 hei \left(a^{2}-a\right)+\left(2a-2\right).
a\left(a-1\right)+2\left(a-1\right)
Tauwehea te a i te tuatahi me te 2 i te rōpū tuarua.
\left(a-1\right)\left(a+2\right)
Whakatauwehea atu te kīanga pātahi a-1 mā te whakamahi i te āhuatanga tātai tohatoha.
a^{2}+a-2=0
Ka taea te huamaha pūrua te tauwehe mā te whakamahi i te huringa ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), ina ko x_{1} me x_{2} ngā otinga o te whārite pūrua ax^{2}+bx+c=0.
a=\frac{-1±\sqrt{1^{2}-4\left(-2\right)}}{2}
Ko ngā whārite katoa o te āhua ax^{2}+bx+c=0 ka taea te whakaoti mā te whakamahi i te tikanga tātai pūrua: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. E rua ngā otinga ka puta i te tikanga tātai pūrua, ko tētahi ina he tāpiri a ±, ā, ko tētahi ina he tango.
a=\frac{-1±\sqrt{1-4\left(-2\right)}}{2}
Pūrua 1.
a=\frac{-1±\sqrt{1+8}}{2}
Whakareatia -4 ki te -2.
a=\frac{-1±\sqrt{9}}{2}
Tāpiri 1 ki te 8.
a=\frac{-1±3}{2}
Tuhia te pūtakerua o te 9.
a=\frac{2}{2}
Nā, me whakaoti te whārite a=\frac{-1±3}{2} ina he tāpiri te ±. Tāpiri -1 ki te 3.
a=1
Whakawehe 2 ki te 2.
a=-\frac{4}{2}
Nā, me whakaoti te whārite a=\frac{-1±3}{2} ina he tango te ±. Tango 3 mai i -1.
a=-2
Whakawehe -4 ki te 2.
a^{2}+a-2=\left(a-1\right)\left(a-\left(-2\right)\right)
Tauwehea te kīanga taketake mā te whakamahi i te ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right). Me whakakapi te 1 mō te x_{1} me te -2 mō te x_{2}.
a^{2}+a-2=\left(a-1\right)\left(a+2\right)
Whakamāmātia ngā kīanga katoa o te āhua p-\left(-q\right) ki te p+q.