Whakaoti i te a^2+7=13

$$a ^ { 2 } + 7 = 13$$

Whakaoti mō a

$$a=\sqrt{6}\approx 2.449489743$$

$$a=-\sqrt{6}\approx -2.449489743$$

Ngā Upane mā te Kimi Pūtakerua

Tangohia te 7 mai i ngā taha e rua.

$$a^{2}=13-7$$

Tangohia te 7 i te 13, ka 6.

$$a^{2}=6$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$a=\sqrt{6} a=-\sqrt{6}$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Tangohia te 13 mai i ngā taha e rua.

$$a^{2}+7-13=0$$

Tangohia te 13 i te 7, ka -6.

$$a^{2}-6=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me -6 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$a=\frac{0±\sqrt{0^{2}-4\left(-6\right)}}{2}$$

Pūrua 0.

$$a=\frac{0±\sqrt{-4\left(-6\right)}}{2}$$

Whakareatia -4 ki te -6.

$$a=\frac{0±\sqrt{24}}{2}$$

Tuhia te pūtakerua o te 24.

$$a=\frac{0±2\sqrt{6}}{2}$$

Nā, me whakaoti te whārite a=\frac{0±2\sqrt{6}}{2} ina he tāpiri te ±.

$$a=\sqrt{6}$$

Nā, me whakaoti te whārite a=\frac{0±2\sqrt{6}}{2} ina he tango te ±.

$$a=-\sqrt{6}$$

Kua oti te whārite te whakatau.

$$a=\sqrt{6} a=-\sqrt{6}$$