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a^{2}+4a=0.001
Ko ngā whārite katoa o te āhua ax^{2}+bx+c=0 ka taea te whakaoti mā te whakamahi i te tikanga tātai pūrua: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. E rua ngā otinga ka puta i te tikanga tātai pūrua, ko tētahi ina he tāpiri a ±, ā, ko tētahi ina he tango.
a^{2}+4a-0.001=0.001-0.001
Me tango 0.001 mai i ngā taha e rua o te whārite.
a^{2}+4a-0.001=0
Mā te tango i te 0.001 i a ia ake anō ka toe ko te 0.
a=\frac{-4±\sqrt{4^{2}-4\left(-0.001\right)}}{2}
Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 4 mō b, me -0.001 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
a=\frac{-4±\sqrt{16-4\left(-0.001\right)}}{2}
Pūrua 4.
a=\frac{-4±\sqrt{16+0.004}}{2}
Whakareatia -4 ki te -0.001.
a=\frac{-4±\sqrt{16.004}}{2}
Tāpiri 16 ki te 0.004.
a=\frac{-4±\frac{\sqrt{40010}}{50}}{2}
Tuhia te pūtakerua o te 16.004.
a=\frac{\frac{\sqrt{40010}}{50}-4}{2}
Nā, me whakaoti te whārite a=\frac{-4±\frac{\sqrt{40010}}{50}}{2} ina he tāpiri te ±. Tāpiri -4 ki te \frac{\sqrt{40010}}{50}.
a=\frac{\sqrt{40010}}{100}-2
Whakawehe -4+\frac{\sqrt{40010}}{50} ki te 2.
a=\frac{-\frac{\sqrt{40010}}{50}-4}{2}
Nā, me whakaoti te whārite a=\frac{-4±\frac{\sqrt{40010}}{50}}{2} ina he tango te ±. Tango \frac{\sqrt{40010}}{50} mai i -4.
a=-\frac{\sqrt{40010}}{100}-2
Whakawehe -4-\frac{\sqrt{40010}}{50} ki te 2.
a=\frac{\sqrt{40010}}{100}-2 a=-\frac{\sqrt{40010}}{100}-2
Kua oti te whārite te whakatau.
a^{2}+4a=0.001
Ko ngā whārite pūrua pēnei i tēnei nā ka taea te whakaoti mā te whakaoti i te pūrua. Hei whakaoti i te pūrua, ko te whārite me mātua tuhi ki te āhua x^{2}+bx=c.
a^{2}+4a+2^{2}=0.001+2^{2}
Whakawehea te 4, te tau whakarea o te kīanga tau x, ki te 2 kia riro ai te 2. Nā, tāpiria te pūrua o te 2 ki ngā taha e rua o te whārite. Mā konei e pūrua tika tonu ai te taha mauī o te whārite.
a^{2}+4a+4=0.001+4
Pūrua 2.
a^{2}+4a+4=4.001
Tāpiri 0.001 ki te 4.
\left(a+2\right)^{2}=4.001
Tauwehea a^{2}+4a+4. Ko te tikanga pūnoa, ina ko x^{2}+bx+c he pūrua tika pūrua tika pū, ka taea taua mea te tauwehea i ngā wā katoa hei \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(a+2\right)^{2}}=\sqrt{4.001}
Tuhia te pūtakerua o ngā taha e rua o te whārite.
a+2=\frac{\sqrt{40010}}{100} a+2=-\frac{\sqrt{40010}}{100}
Whakarūnātia.
a=\frac{\sqrt{40010}}{100}-2 a=-\frac{\sqrt{40010}}{100}-2
Me tango 2 mai i ngā taha e rua o te whārite.