Whakaoti i te a^2+4^2=8^2

$$a ^ { 2 } + 4 ^ { 2 } = 8 ^ { 2 }$$

Whakaoti mō a

$$a=4\sqrt{3}\approx 6.92820323$$

$$a=-4\sqrt{3}\approx -6.92820323$$

Ngā Upane mā te Kimi Pūtakerua

Tātaihia te 4 mā te pū o 2, kia riro ko 16.

$$a^{2}+16=8^{2}$$

Tātaihia te 8 mā te pū o 2, kia riro ko 64.

$$a^{2}+16=64$$

Tangohia te 16 mai i ngā taha e rua.

$$a^{2}=64-16$$

Tangohia te 16 i te 64, ka 48.

$$a^{2}=48$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$a=4\sqrt{3} a=-4\sqrt{3}$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Tātaihia te 4 mā te pū o 2, kia riro ko 16.

$$a^{2}+16=8^{2}$$

Tātaihia te 8 mā te pū o 2, kia riro ko 64.

$$a^{2}+16=64$$

Tangohia te 64 mai i ngā taha e rua.

$$a^{2}+16-64=0$$

Tangohia te 64 i te 16, ka -48.

$$a^{2}-48=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me -48 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$a=\frac{0±\sqrt{0^{2}-4\left(-48\right)}}{2}$$

Pūrua 0.

$$a=\frac{0±\sqrt{-4\left(-48\right)}}{2}$$

Whakareatia -4 ki te -48.

$$a=\frac{0±\sqrt{192}}{2}$$

Tuhia te pūtakerua o te 192.

$$a=\frac{0±8\sqrt{3}}{2}$$

Nā, me whakaoti te whārite a=\frac{0±8\sqrt{3}}{2} ina he tāpiri te ±.

$$a=4\sqrt{3}$$

Nā, me whakaoti te whārite a=\frac{0±8\sqrt{3}}{2} ina he tango te ±.

$$a=-4\sqrt{3}$$

Kua oti te whārite te whakatau.

$$a=4\sqrt{3} a=-4\sqrt{3}$$