Whakaoti i te a^2+2a+1=0

$$a ^ { 2 } + 2 a + 1 = 0$$

Whakaoti mō a

$$a=-1$$

Ngā Upane Whakamahi Tauwehe

Hei whakaoti i te whārite, whakatauwehea te a^{2}+2a+1 mā te whakamahi i te tātai a^{2}+\left(a+b\right)a+ab=\left(a+a\right)\left(a+b\right). Hei kimi a me b, whakaritea tētahi pūnaha kia whakaoti.

$$a+b=2 ab=1$$

I te mea kua tōrunga te ab, he ōrite te tohu o a me b. I te mea kua tōrunga te a+b, he tōrunga hoki a a me b. Ko te takirua anake pērā ko te otinga pūnaha.

$$a=1 b=1$$

Me tuhi anō te kīanga whakatauwehe \left(a+a\right)\left(a+b\right) mā ngā uara i tātaihia.

$$\left(a+1\right)\left(a+1\right)$$

Tuhia anōtia hei pūrua huarua.

$$\left(a+1\right)^{2}$$

Hei kimi i te otinga whārite, whakaotia te a+1=0.

$$a=-1$$

Ngā Upane Whakamahi Tauwehe Mā te Whakarōpū

Hei whakaoti i te whārite, whakatauwehea te taha mauī mā te whakarōpū. Tuatahi, me tuhi anō te taha mauī hei a^{2}+aa+ba+1. Hei kimi a me b, whakaritea tētahi pūnaha kia whakaoti.

$$a+b=2 ab=1\times 1=1$$

I te mea kua tōrunga te ab, he ōrite te tohu o a me b. I te mea kua tōrunga te a+b, he tōrunga hoki a a me b. Ko te takirua anake pērā ko te otinga pūnaha.

$$a=1 b=1$$

Tuhia anō te a^{2}+2a+1 hei \left(a^{2}+a\right)+\left(a+1\right).

$$\left(a^{2}+a\right)+\left(a+1\right)$$

Whakatauwehea atu a i te a^{2}+a.

$$a\left(a+1\right)+a+1$$

Whakatauwehea atu te kīanga pātahi a+1 mā te whakamahi i te āhuatanga tātai tohatoha.

$$\left(a+1\right)\left(a+1\right)$$

Tuhia anōtia hei pūrua huarua.

$$\left(a+1\right)^{2}$$

Hei kimi i te otinga whārite, whakaotia te a+1=0.

$$a=-1$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Ko ngā whārite katoa o te āhua ax^{2}+bx+c=0 ka taea te whakaoti mā te whakamahi i te tikanga tātai pūrua: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. E rua ngā otinga ka puta i te tikanga tātai pūrua, ko tētahi ina he tāpiri a ±, ā, ko tētahi ina he tango.

$$a^{2}+2a+1=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 2 mō b, me 1 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$a=\frac{-2±\sqrt{2^{2}-4}}{2}$$

Pūrua 2.

$$a=\frac{-2±\sqrt{4-4}}{2}$$

Tāpiri 4 ki te -4.

$$a=\frac{-2±\sqrt{0}}{2}$$

Tuhia te pūtakerua o te 0.

$$a=-\frac{2}{2}$$

Whakawehe -2 ki te 2.

$$a=-1$$

Ngā Upane mō te Whakaoti i te Pūrua

Tauwehea a^{2}+2a+1. Ko te tikanga pūnoa, ina ko x^{2}+bx+c he pūrua tika pūrua tika pū, ka taea taua mea te tauwehea i ngā wā katoa hei \left(x+\frac{b}{2}\right)^{2}.

$$\left(a+1\right)^{2}=0$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$\sqrt{\left(a+1\right)^{2}}=\sqrt{0}$$

Whakarūnātia.

$$a+1=0 a+1=0$$

Me tango 1 mai i ngā taha e rua o te whārite.

$$a=-1 a=-1$$

Kua oti te whārite te whakatau. He ōrite ngā whakatau.

$$a=-1$$