Whakaoti i te Y=2(x+3)^2-4,quadx=-5 | Kairarau Microsoft

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Whakaoti mō Y, x

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5 raruraru e ōrite ana ki:

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https://socratic.org/questions/how-do-you-find-the-roots-real-and-imaginary-of-y-2-x-3-2-x-3-2-using-the-quadra

https://socratic.org/questions/what-is-the-center-and-radius-of-the-circle-with-equation-x-3-2-y-8-2-49

https://socratic.org/questions/how-do-you-find-the-roots-real-and-imaginary-of-y-2-x-3-2-7x-5-using-the-quadrat

https://socratic.org/questions/two-circles-have-the-following-equations-x-1-2-y-4-2-25-and-x-3-2-y-3-2-49-does-

https://socratic.org/questions/how-do-you-find-the-roots-real-and-imaginary-of-y-x-2-3-x-2-2-using-the-quadrati

Tohaina

Kua tāruatia ki te papatopenga

Y=2\left(-5+3\right)^{2}-4

Whakaarohia te whārite tuatahi. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

Y=2\left(-2\right)^{2}-4

Tāpirihia te -5 ki te 3, ka -2.

Y=2\times 4-4

Tātaihia te -2 mā te pū o 2, kia riro ko 4.

Y=8-4

Whakareatia te 2 ki te 4, ka 8.

Y=4

Tangohia te 4 i te 8, ka 4.

Y=4 x=-5

Kua oti te pūnaha te whakatau.

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