Whakaoti mō B (complex solution)
\left\{\begin{matrix}B=\frac{X}{\left(2x+3\right)^{2}}\text{, }&x\neq -\frac{3}{2}\\B\in \mathrm{C}\text{, }&X=0\text{ and }x=-\frac{3}{2}\end{matrix}\right.
Whakaoti mō B
\left\{\begin{matrix}B=\frac{X}{\left(2x+3\right)^{2}}\text{, }&x\neq -\frac{3}{2}\\B\in \mathrm{R}\text{, }&X=0\text{ and }x=-\frac{3}{2}\end{matrix}\right.
Whakaoti mō X
X=B\left(2x+3\right)^{2}
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Tohaina
Kua tāruatia ki te papatopenga
X=\left(4x^{2}+12x+9\right)B
Whakamahia te ture huarua \left(a+b\right)^{2}=a^{2}+2ab+b^{2} hei whakaroha \left(2x+3\right)^{2}.
X=4x^{2}B+12xB+9B
Whakamahia te āhuatanga tohatoha hei whakarea te 4x^{2}+12x+9 ki te B.
4x^{2}B+12xB+9B=X
Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.
\left(4x^{2}+12x+9\right)B=X
Pahekotia ngā kīanga tau katoa e whai ana i te B.
\frac{\left(4x^{2}+12x+9\right)B}{4x^{2}+12x+9}=\frac{X}{4x^{2}+12x+9}
Whakawehea ngā taha e rua ki te 4x^{2}+12x+9.
B=\frac{X}{4x^{2}+12x+9}
Mā te whakawehe ki te 4x^{2}+12x+9 ka wetekia te whakareanga ki te 4x^{2}+12x+9.
B=\frac{X}{\left(2x+3\right)^{2}}
Whakawehe X ki te 4x^{2}+12x+9.
X=\left(4x^{2}+12x+9\right)B
Whakamahia te ture huarua \left(a+b\right)^{2}=a^{2}+2ab+b^{2} hei whakaroha \left(2x+3\right)^{2}.
X=4x^{2}B+12xB+9B
Whakamahia te āhuatanga tohatoha hei whakarea te 4x^{2}+12x+9 ki te B.
4x^{2}B+12xB+9B=X
Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.
\left(4x^{2}+12x+9\right)B=X
Pahekotia ngā kīanga tau katoa e whai ana i te B.
\frac{\left(4x^{2}+12x+9\right)B}{4x^{2}+12x+9}=\frac{X}{4x^{2}+12x+9}
Whakawehea ngā taha e rua ki te 4x^{2}+12x+9.
B=\frac{X}{4x^{2}+12x+9}
Mā te whakawehe ki te 4x^{2}+12x+9 ka wetekia te whakareanga ki te 4x^{2}+12x+9.
B=\frac{X}{\left(2x+3\right)^{2}}
Whakawehe X ki te 4x^{2}+12x+9.
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