Whakaoti i te V_{3}=15.2m/segquadv_{4}=21.0m/seg

$$V _ { 3 } = 15.2 m / seg \quad v _ { 4 } = 21.0 m / seg$$

Aromātai (complex solution)

$$V_{3}=\frac{76egmv_{4}}{5s}\text{ and }\frac{76egmv_{4}}{5s}=\frac{21egm}{s}$$

Whakaoti mō v_4

$$\left\{\begin{matrix}v_{4}=\frac{5V_{3}s}{76egm}\text{, }&V_{3}=\frac{21egm}{s}\text{ and }g\neq 0\text{ and }s\neq 0\text{ and }m\neq 0\\v_{4}\in \mathrm{R}\text{, }&\left(g=0\text{ or }m=0\right)\text{ and }V_{3}=0\text{ and }s\neq 0\end{matrix}\right.$$

Whakaoti mō s

$$\left\{\begin{matrix}s=\frac{21egm}{V_{3}}\text{, }&v_{4}=\frac{105}{76}\text{ and }g\neq 0\text{ and }m\neq 0\text{ and }V_{3}\neq 0\\s\neq 0\text{, }&\left(m=0\text{ or }g=0\right)\text{ and }V_{3}=0\end{matrix}\right.$$