Whakaoti i te T=2pisqrt{l/9.8}quad[2]

$$T = 2 \pi \sqrt { \frac { l } { 9.8 } } \quad [ 2 ]$$

Whakaoti mō l

$$l=\frac{49\times \left(\frac{T}{\pi }\right)^{2}}{80}$$

$$T\geq 0$$

Ngā Upane mō te Whakaoti Whārite Pūtake

Whakareatia te 2 ki te 2, ka 4.

$$T=4\pi \sqrt{\frac{l}{9.8}}$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$4\pi \sqrt{\frac{l}{9.8}}=T$$

Whakawehea ngā taha e rua ki te 4\pi .

$$\frac{4\pi \sqrt{\frac{5}{49}l}}{4\pi }=\frac{T}{4\pi }$$

Mā te whakawehe ki te 4\pi ka wetekia te whakareanga ki te 4\pi .

$$\sqrt{\frac{5}{49}l}=\frac{T}{4\pi }$$

Pūruatia ngā taha e rua o te whārite.

$$\frac{5}{49}l=\frac{T^{2}}{16\pi ^{2}}$$

Whakawehea ngā taha e rua o te whārite ki te \frac{5}{49}, he ōrite ki te whakarea i ngā taha e rua ki te tau huripoki o te hautanga.

$$\frac{\frac{5}{49}l}{\frac{5}{49}}=\frac{T^{2}}{\frac{5}{49}\times 16\pi ^{2}}$$

Mā te whakawehe ki te \frac{5}{49} ka wetekia te whakareanga ki te \frac{5}{49}.

$$l=\frac{T^{2}}{\frac{5}{49}\times 16\pi ^{2}}$$

Whakawehe \frac{T^{2}}{16\pi ^{2}} ki te \frac{5}{49} mā te whakarea \frac{T^{2}}{16\pi ^{2}} ki te tau huripoki o \frac{5}{49}.

$$l=\frac{49T^{2}}{80\pi ^{2}}$$

Whakaoti mō T

$$T=\frac{4\pi \sqrt{5l}}{7}$$

$$l\geq 0$$