Whakaoti i te T=2pisqrt{L/980}

$$T = 2 \pi \sqrt { \frac { L } { 980 } }$$

Whakaoti mō L

$$L=245\times \left(\frac{T}{\pi }\right)^{2}$$

$$T\geq 0$$

Ngā Upane mō te Whakaoti Whārite Pūtake

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$2\pi \sqrt{\frac{L}{980}}=T$$

Whakawehea ngā taha e rua ki te 2\pi .

$$\frac{2\pi \sqrt{\frac{1}{980}L}}{2\pi }=\frac{T}{2\pi }$$

Mā te whakawehe ki te 2\pi ka wetekia te whakareanga ki te 2\pi .

$$\sqrt{\frac{1}{980}L}=\frac{T}{2\pi }$$

Pūruatia ngā taha e rua o te whārite.

$$\frac{1}{980}L=\frac{T^{2}}{4\pi ^{2}}$$

Me whakarea ngā taha e rua ki te 980.

$$\frac{\frac{1}{980}L}{\frac{1}{980}}=\frac{T^{2}}{\frac{1}{980}\times 4\pi ^{2}}$$

Mā te whakawehe ki te \frac{1}{980} ka wetekia te whakareanga ki te \frac{1}{980}.

$$L=\frac{T^{2}}{\frac{1}{980}\times 4\pi ^{2}}$$

Whakawehe \frac{T^{2}}{4\pi ^{2}} ki te \frac{1}{980} mā te whakarea \frac{T^{2}}{4\pi ^{2}} ki te tau huripoki o \frac{1}{980}.

$$L=\frac{245T^{2}}{\pi ^{2}}$$

Whakaoti mō T

$$T=\frac{\pi \sqrt{5L}}{35}$$

$$L\geq 0$$