Whakaoti mō n (complex solution)
n=-\frac{\sqrt{3\left(S_{n}-2\right)}}{3}
n=\frac{\sqrt{3\left(S_{n}-2\right)}}{3}
Whakaoti mō S_n
S_{n}=3n^{2}+2
Whakaoti mō n
n=\frac{\sqrt{3\left(S_{n}-2\right)}}{3}
n=-\frac{\sqrt{3\left(S_{n}-2\right)}}{3}\text{, }S_{n}\geq 2
Tohaina
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