Whakaoti i te SEmeomegan=0.6/sqrt{25}

$$S E m e \omega n = \frac { 0.6 } { \sqrt { 25 } }$$

Whakaoti mō E

$$E=\frac{3}{25eSmn\omega }$$

$$n\neq 0\text{ and }\omega \neq 0\text{ and }m\neq 0\text{ and }S\neq 0$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tātaitia te pūtakerua o 25 kia tae ki 5.

$$SEme\omega n=\frac{0.6}{5}$$

Whakarohaina te \frac{0.6}{5} mā te whakarea i te taurunga me te tauraro ki te 10.

$$SEme\omega n=\frac{6}{50}$$

Whakahekea te hautanga \frac{6}{50} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 2.

$$SEme\omega n=\frac{3}{25}$$

He hanga arowhānui tō te whārite.

$$eSmn\omega E=\frac{3}{25}$$

Whakawehea ngā taha e rua ki te Sme\omega n.

$$\frac{eSmn\omega E}{eSmn\omega }=\frac{\frac{3}{25}}{eSmn\omega }$$

Mā te whakawehe ki te Sme\omega n ka wetekia te whakareanga ki te Sme\omega n.

$$E=\frac{\frac{3}{25}}{eSmn\omega }$$

Whakawehe \frac{3}{25} ki te Sme\omega n.

$$E=\frac{3}{25eSmn\omega }$$

Whakaoti mō S

$$S=\frac{3}{25eEmn\omega }$$

$$n\neq 0\text{ and }\omega \neq 0\text{ and }m\neq 0\text{ and }E\neq 0$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tātaitia te pūtakerua o 25 kia tae ki 5.

$$SEme\omega n=\frac{0.6}{5}$$

Whakarohaina te \frac{0.6}{5} mā te whakarea i te taurunga me te tauraro ki te 10.

$$SEme\omega n=\frac{6}{50}$$

Whakahekea te hautanga \frac{6}{50} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 2.

$$SEme\omega n=\frac{3}{25}$$

He hanga arowhānui tō te whārite.

$$eEmn\omega S=\frac{3}{25}$$

Whakawehea ngā taha e rua ki te Eme\omega n.

$$\frac{eEmn\omega S}{eEmn\omega }=\frac{\frac{3}{25}}{eEmn\omega }$$

Mā te whakawehe ki te Eme\omega n ka wetekia te whakareanga ki te Eme\omega n.

$$S=\frac{\frac{3}{25}}{eEmn\omega }$$

Whakawehe \frac{3}{25} ki te Eme\omega n.

$$S=\frac{3}{25eEmn\omega }$$