Whakaoti i te SB=S+beta

$$S B = S + \beta$$

Whakaoti mō B (complex solution)

$$\left\{\begin{matrix}B=\frac{S+\beta }{S}\text{, }&S\neq 0\\B\in \mathrm{C}\text{, }&S=0\text{ and }\beta =0\end{matrix}\right.$$

Ngā Upane mō te Whakaoti Whārite Rārangi

He hanga arowhānui tō te whārite.

$$SB=S+\beta$$

Whakawehea ngā taha e rua ki te S.

$$\frac{SB}{S}=\frac{S+\beta }{S}$$

Mā te whakawehe ki te S ka wetekia te whakareanga ki te S.

$$B=\frac{S+\beta }{S}$$

Whakaoti mō S (complex solution)

$$\left\{\begin{matrix}S=\frac{\beta }{B-1}\text{, }&B\neq 1\\S\in \mathrm{C}\text{, }&\beta =0\text{ and }B=1\end{matrix}\right.$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tangohia te S mai i ngā taha e rua.

$$SB-S=\beta$$

Pahekotia ngā kīanga tau katoa e whai ana i te S.

$$\left(B-1\right)S=\beta$$

Whakawehea ngā taha e rua ki te B-1.

$$\frac{\left(B-1\right)S}{B-1}=\frac{\beta }{B-1}$$

Mā te whakawehe ki te B-1 ka wetekia te whakareanga ki te B-1.

$$S=\frac{\beta }{B-1}$$

Whakaoti mō B

$$\left\{\begin{matrix}B=\frac{S+\beta }{S}\text{, }&S\neq 0\\B\in \mathrm{R}\text{, }&S=0\text{ and }\beta =0\end{matrix}\right.$$

Ngā Upane mō te Whakaoti Whārite Rārangi

He hanga arowhānui tō te whārite.

$$SB=S+\beta$$

Whakawehea ngā taha e rua ki te S.

$$\frac{SB}{S}=\frac{S+\beta }{S}$$

Mā te whakawehe ki te S ka wetekia te whakareanga ki te S.

$$B=\frac{S+\beta }{S}$$

Whakaoti mō S

$$\left\{\begin{matrix}S=\frac{\beta }{B-1}\text{, }&B\neq 1\\S\in \mathrm{R}\text{, }&\beta =0\text{ and }B=1\end{matrix}\right.$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tangohia te S mai i ngā taha e rua.

$$SB-S=\beta$$

Pahekotia ngā kīanga tau katoa e whai ana i te S.

$$\left(B-1\right)S=\beta$$

Whakawehea ngā taha e rua ki te B-1.

$$\frac{\left(B-1\right)S}{B-1}=\frac{\beta }{B-1}$$

Mā te whakawehe ki te B-1 ka wetekia te whakareanga ki te B-1.

$$S=\frac{\beta }{B-1}$$