Whakaoti i te S1/x^2-2x-1/x^2+2x

$$S \frac { 1 } { x ^ { 2 } - 2 x } - \frac { 1 } { x ^ { 2 } + 2 x }$$

Aromātai

$$\frac{Sx-x+2S+2}{x\left(x^{2}-4\right)}$$

$$x\neq 0\text{ and }|x|\neq 2$$

Ngā Hipanga Rongoā Poto

Tuhia te S\times \frac{1}{x^{2}-2x} hei hautanga kotahi.

$$\frac{S}{x^{2}-2x}-\frac{1}{x^{2}+2x}$$

Tauwehea te x^{2}-2x. Tauwehea te x^{2}+2x.

$$\frac{S}{x\left(x-2\right)}-\frac{1}{x\left(x+2\right)}$$

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Ko te taurea pātahi iti rawa o x\left(x-2\right) me x\left(x+2\right) ko x\left(x-2\right)\left(x+2\right). Whakareatia \frac{S}{x\left(x-2\right)} ki te \frac{x+2}{x+2}. Whakareatia \frac{1}{x\left(x+2\right)} ki te \frac{x-2}{x-2}.

$$\frac{S\left(x+2\right)}{x\left(x-2\right)\left(x+2\right)}-\frac{x-2}{x\left(x-2\right)\left(x+2\right)}$$

Tā te mea he rite te tauraro o \frac{S\left(x+2\right)}{x\left(x-2\right)\left(x+2\right)} me \frac{x-2}{x\left(x-2\right)\left(x+2\right)}, me tango rāua mā te tango i ō raua taurunga.

$$\frac{S\left(x+2\right)-\left(x-2\right)}{x\left(x-2\right)\left(x+2\right)}$$

Mahia ngā whakarea i roto o S\left(x+2\right)-\left(x-2\right).

$$\frac{Sx+2S-x+2}{x\left(x-2\right)\left(x+2\right)}$$

Whakarohaina te x\left(x-2\right)\left(x+2\right).

$$\frac{Sx+2S-x+2}{x^{3}-4x}$$

Kimi Pārōnaki e ai ki x

$$\frac{2\left(4+4S-3x^{2}-3Sx^{2}+x^{3}-Sx^{3}\right)}{\left(x\left(x^{2}-4\right)\right)^{2}}$$

$$x\neq 0\text{ and }|x|\neq 2$$