Whakaoti i te S=u+1/2at^2

$$S = u + \frac { 1 } { 2 } a t ^ { 2 }$$

Whakaoti mō a

$$\left\{\begin{matrix}a=-\frac{2\left(u-S\right)}{t^{2}}\text{, }&t\neq 0\\a\in \mathrm{R}\text{, }&S=u\text{ and }t=0\end{matrix}\right.$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$u+\frac{1}{2}at^{2}=S$$

Tangohia te u mai i ngā taha e rua.

$$\frac{1}{2}at^{2}=S-u$$

He hanga arowhānui tō te whārite.

$$\frac{t^{2}}{2}a=S-u$$

Whakawehea ngā taha e rua ki te \frac{1}{2}t^{2}.

$$\frac{2\times \frac{t^{2}}{2}a}{t^{2}}=\frac{2\left(S-u\right)}{t^{2}}$$

Mā te whakawehe ki te \frac{1}{2}t^{2} ka wetekia te whakareanga ki te \frac{1}{2}t^{2}.

$$a=\frac{2\left(S-u\right)}{t^{2}}$$

Whakaoti mō S

$$S=\frac{at^{2}}{2}+u$$