Whakaoti i te R(46)=233x-01x^2

$$R ( 46 ) = 233 x - 01 x ^ { 2 }$$

Aromātai

$$233x$$

Ngā Upane Otinga

Whakareatia te 0 ki te 1, ka 0.

$$233x-0x^{2}$$

Ko te tau i whakarea ki te kore ka hua ko te kore.

$$233x-0$$

Kimi Pārōnaki e ai ki x

$$233$$

Ngā Upane e Whakamahi ana i te Tautuhinga o te Pārōnaki

Whakareatia te 0 ki te 1, ka 0.

$$\frac{\mathrm{d}}{\mathrm{d}x}(233x-0x^{2})$$

Ko te tau i whakarea ki te kore ka hua ko te kore.

$$\frac{\mathrm{d}}{\mathrm{d}x}(233x-0)$$

Whakareatia te -1 ki te 0, ka 0.

$$\frac{\mathrm{d}}{\mathrm{d}x}(233x+0)$$

Ko te tau i tāpiria he kore ka hua koia tonu.

$$\frac{\mathrm{d}}{\mathrm{d}x}(233x)$$

Ko te pārōnaki o ax^{n} ko nax^{n-1}.

$$233x^{1-1}$$

Tango 1 mai i 1.

$$233x^{0}$$

Mō tētahi kupu t mahue te 0, t^{0}=1.

$$233\times 1$$

Mō tētahi kupu t, t\times 1=t me 1t=t.

$$233$$