Whakaoti i te R^2-4=0

$$R ^ { 2 } - 4 = 0$$

Whakaoti mō R

$$R=2$$

$$R=-2$$

Ngā Hipanga Whakamahi Rerekētanga o ngā Pūrua

Whakaarohia te R^{2}-4. Tuhia anō te R^{2}-4 hei R^{2}-2^{2}. Ka taea te rerekētanga o ngā pūrua te whakatauwehe mā te ture: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).

$$\left(R-2\right)\left(R+2\right)=0$$

Hei kimi otinga whārite, me whakaoti te R-2=0 me te R+2=0.

$$R=2 R=-2$$

Ngā Upane mā te Kimi Pūtakerua

Me tāpiri te 4 ki ngā taha e rua. Ko te tau i tāpiria he kore ka hua koia tonu.

$$R^{2}=4$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$R=2 R=-2$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Ko ngā tikanga tātai pūrua pēnei i tēnei nā, me te kīanga tau x^{2} engari kāore he kīanga tau x, ka taea tonu te whakaoti mā te whakamahi i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, ina tuhia ki te tānga ngahuru: ax^{2}+bx+c=0.

$$R^{2}-4=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me -4 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$R=\frac{0±\sqrt{0^{2}-4\left(-4\right)}}{2}$$

Pūrua 0.

$$R=\frac{0±\sqrt{-4\left(-4\right)}}{2}$$

Whakareatia -4 ki te -4.

$$R=\frac{0±\sqrt{16}}{2}$$

Tuhia te pūtakerua o te 16.

$$R=\frac{0±4}{2}$$

Nā, me whakaoti te whārite R=\frac{0±4}{2} ina he tāpiri te ±. Whakawehe 4 ki te 2.

$$R=2$$

Nā, me whakaoti te whārite R=\frac{0±4}{2} ina he tango te ±. Whakawehe -4 ki te 2.

$$R=-2$$

Kua oti te whārite te whakatau.

$$R=2 R=-2$$