Whakaoti i te P_{1}=P_{2}e^-bu

$$P _ { 1 } = P _ { 2 } e ^ { - b u }$$

Whakaoti mō P_2

$$P_{2}=P_{1}e^{bu}$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$P_{2}e^{\left(-b\right)u}=P_{1}$$

Whakaraupapatia anō ngā kīanga tau.

$$P_{2}e^{-bu}=P_{1}$$

He hanga arowhānui tō te whārite.

$$\frac{1}{e^{bu}}P_{2}=P_{1}$$

Whakawehea ngā taha e rua ki te e^{-bu}.

$$\frac{\frac{1}{e^{bu}}P_{2}e^{bu}}{1}=\frac{P_{1}e^{bu}}{1}$$

Mā te whakawehe ki te e^{-bu} ka wetekia te whakareanga ki te e^{-bu}.

$$P_{2}=\frac{P_{1}e^{bu}}{1}$$

Whakawehe P_{1} ki te e^{-bu}.

$$P_{2}=P_{1}e^{bu}$$

Whakaoti mō P_1

$$P_{1}=\frac{P_{2}}{e^{bu}}$$