Whakaoti i te P(x)=3x^2-5x+1quadL(x)=x^2-7x-3

$$P ( x ) = 3 x ^ { 2 } - 5 x + 1 \quad L ( x ) = x ^ { 2 } - 7 x - 3$$

Whakaoti mō L

$$L=-2x-2-\frac{3}{x}$$

$$x\neq 0$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tangohia te 3x^{2} mai i ngā taha e rua.

$$-5x+1Lx=x^{2}-7x-3-3x^{2}$$

Pahekotia te x^{2} me -3x^{2}, ka -2x^{2}.

$$-5x+1Lx=-2x^{2}-7x-3$$

Me tāpiri te 5x ki ngā taha e rua.

$$1Lx=-2x^{2}-7x-3+5x$$

Pahekotia te -7x me 5x, ka -2x.

$$1Lx=-2x^{2}-2x-3$$

Whakaraupapatia anō ngā kīanga tau.

$$Lx=-2x^{2}-2x-3$$

He hanga arowhānui tō te whārite.

$$xL=-2x^{2}-2x-3$$

Whakawehea ngā taha e rua ki te x.

$$\frac{xL}{x}=\frac{-2x^{2}-2x-3}{x}$$

Mā te whakawehe ki te x ka wetekia te whakareanga ki te x.

$$L=\frac{-2x^{2}-2x-3}{x}$$

Whakawehe -2x^{2}-2x-3 ki te x.

$$L=-2x-2-\frac{3}{x}$$

Whakaoti mō x (complex solution)

$$x=\frac{\sqrt{L^{2}+4L-20}}{4}-\frac{L}{4}-\frac{1}{2}$$

$$x=-\frac{\sqrt{L^{2}+4L-20}}{4}-\frac{L}{4}-\frac{1}{2}$$

Whakaoti mō x

$$x=\frac{\sqrt{L^{2}+4L-20}}{4}-\frac{L}{4}-\frac{1}{2}$$

$$x=-\frac{\sqrt{L^{2}+4L-20}}{4}-\frac{L}{4}-\frac{1}{2}\text{, }L\geq 2\sqrt{6}-2\text{ or }L\leq -2\sqrt{6}-2$$