Whakaoti i te P^2-5=-4

$$P ^ { 2 } - 5 = - 4$$

Whakaoti mō P

$$P=1$$

$$P=-1$$

Ngā Hipanga Whakamahi Rerekētanga o ngā Pūrua

Me tāpiri te 4 ki ngā taha e rua.

$$P^{2}-5+4=0$$

Tāpirihia te -5 ki te 4, ka -1.

$$P^{2}-1=0$$

Whakaarohia te P^{2}-1. Tuhia anō te P^{2}-1 hei P^{2}-1^{2}. Ka taea te rerekētanga o ngā pūrua te whakatauwehe mā te ture: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).

$$\left(P-1\right)\left(P+1\right)=0$$

Hei kimi otinga whārite, me whakaoti te P-1=0 me te P+1=0.

$$P=1 P=-1$$

Ngā Upane mā te Kimi Pūtakerua

Me tāpiri te 5 ki ngā taha e rua.

$$P^{2}=-4+5$$

Tāpirihia te -4 ki te 5, ka 1.

$$P^{2}=1$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$P=1 P=-1$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Me tāpiri te 4 ki ngā taha e rua.

$$P^{2}-5+4=0$$

Tāpirihia te -5 ki te 4, ka -1.

$$P^{2}-1=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me -1 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$P=\frac{0±\sqrt{0^{2}-4\left(-1\right)}}{2}$$

Pūrua 0.

$$P=\frac{0±\sqrt{-4\left(-1\right)}}{2}$$

Whakareatia -4 ki te -1.

$$P=\frac{0±\sqrt{4}}{2}$$

Tuhia te pūtakerua o te 4.

$$P=\frac{0±2}{2}$$

Nā, me whakaoti te whārite P=\frac{0±2}{2} ina he tāpiri te ±. Whakawehe 2 ki te 2.

$$P=1$$

Nā, me whakaoti te whārite P=\frac{0±2}{2} ina he tango te ±. Whakawehe -2 ki te 2.

$$P=-1$$

Kua oti te whārite te whakatau.

$$P=1 P=-1$$