Whakaoti i te O*17+3sqrt{(1-017)/15}

$$O \cdot 17 + 3 \sqrt { \frac { ( 1 - 017 ) } { 15 } }$$

Aromātai

$$17O+\frac{\sqrt{15}}{5}$$

Ngā Hipanga Rongoā Poto

Whakareatia te 0 ki te 17, ka 0.

$$O\times 17+3\sqrt{\frac{1-0}{15}}$$

Tangohia te 0 i te 1, ka 1.

$$O\times 17+3\sqrt{\frac{1}{15}}$$

Tuhia anō te pūtake rua o te whakawehenga \sqrt{\frac{1}{15}} hei whakawehenga o ngā pūtake rua \frac{\sqrt{1}}{\sqrt{15}}.

$$O\times 17+3\times \frac{\sqrt{1}}{\sqrt{15}}$$

Tātaitia te pūtakerua o 1 kia tae ki 1.

$$O\times 17+3\times \frac{1}{\sqrt{15}}$$

Whakangāwaritia te tauraro o \frac{1}{\sqrt{15}} mā te whakarea i te taurunga me te tauraro ki te \sqrt{15}.

$$O\times 17+3\times \frac{\sqrt{15}}{\left(\sqrt{15}\right)^{2}}$$

Ko te pūrua o \sqrt{15} ko 15.

$$O\times 17+3\times \frac{\sqrt{15}}{15}$$

Whakakorea atu te tauwehe pūnoa nui rawa 15 i roto i te 3 me te 15.

$$O\times 17+\frac{\sqrt{15}}{5}$$

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Whakareatia O\times 17 ki te \frac{5}{5}.

$$\frac{5O\times 17}{5}+\frac{\sqrt{15}}{5}$$

Tā te mea he rite te tauraro o \frac{5O\times 17}{5} me \frac{\sqrt{15}}{5}, me tāpiri rāua mā te tāpiri i ō raua taurunga.

$$\frac{5O\times 17+\sqrt{15}}{5}$$

Mahia ngā whakarea i roto o 5O\times 17+\sqrt{15}.

$$\frac{85O+\sqrt{15}}{5}$$

Kimi Pārōnaki e ai ki O

$$17$$