Whakaoti i te F(x)=x^3-15x^2+160x-120

$$F ( x ) = x ^ { 3 } - 15 x ^ { 2 } + 160 x - 120$$

Kimi Pārōnaki e ai ki x

$$3x^{2}-30x+160$$

Ngā Upane e Whakamahi ana i te Ture Pārōnaki mō te Tapeke

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

$$3x^{3-1}+2\left(-15\right)x^{2-1}+160x^{1-1}$$

Tango 1 mai i 3.

$$3x^{2}+2\left(-15\right)x^{2-1}+160x^{1-1}$$

Whakareatia 2 ki te -15.

$$3x^{2}-30x^{2-1}+160x^{1-1}$$

Tango 1 mai i 2.

$$3x^{2}-30x^{1}+160x^{1-1}$$

Tango 1 mai i 1.

$$3x^{2}-30x^{1}+160x^{0}$$

Mō tētahi kupu t, t^{1}=t.

$$3x^{2}-30x+160x^{0}$$

Mō tētahi kupu t mahue te 0, t^{0}=1.

$$3x^{2}-30x+160\times 1$$

Mō tētahi kupu t, t\times 1=t me 1t=t.

$$3x^{2}-30x+160$$

Aromātai

$$x^{3}-15x^{2}+160x-120$$