Whakaoti i te F(-6)=6x^3+12x^2-50x+1

$$F ( - 6 ) = 6 x ^ { 3 } + 12 x ^ { 2 } - 50 x + 1$$

Kimi Pārōnaki e ai ki x

$$18x^{2}+24x-50$$

Ngā Upane e Whakamahi ana i te Ture Pārōnaki mō te Tapeke

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

$$3\times 6x^{3-1}+2\times 12x^{2-1}-50x^{1-1}$$

Whakareatia 3 ki te 6.

$$18x^{3-1}+2\times 12x^{2-1}-50x^{1-1}$$

Tango 1 mai i 3.

$$18x^{2}+2\times 12x^{2-1}-50x^{1-1}$$

Whakareatia 2 ki te 12.

$$18x^{2}+24x^{2-1}-50x^{1-1}$$

Tango 1 mai i 2.

$$18x^{2}+24x^{1}-50x^{1-1}$$

Tango 1 mai i 1.

$$18x^{2}+24x^{1}-50x^{0}$$

Mō tētahi kupu t, t^{1}=t.

$$18x^{2}+24x-50x^{0}$$

Mō tētahi kupu t mahue te 0, t^{0}=1.

$$18x^{2}+24x-50$$

Aromātai

$$6x^{3}+12x^{2}-50x+1$$