Kimi Pārōnaki e ai ki F_1625
\frac{1}{25} = 0.04
Aromātai
\frac{F_{1625}}{25}
Pātaitai
Polynomial
F \quad 1625 : 25
Tohaina
Kua tāruatia ki te papatopenga
\frac{1}{25}F_{1625}^{1-1}
Ko te pārōnaki o ax^{n} ko nax^{n-1}.
\frac{1}{25}F_{1625}^{0}
Tango 1 mai i 1.
\frac{1}{25}\times 1
Mō tētahi kupu t mahue te 0, t^{0}=1.
\frac{1}{25}
Mō tētahi kupu t, t\times 1=t me 1t=t.
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