Whakaoti i te F=mg+mv^2/2

$$F = m g + \frac { m v ^ { 2 } } { 2 }$$

Whakaoti mō g

$$\left\{\begin{matrix}g=-\frac{v^{2}}{2}+\frac{F}{m}\text{, }&m\neq 0\\g\in \mathrm{R}\text{, }&F=0\text{ and }m=0\end{matrix}\right.$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$mg+\frac{mv^{2}}{2}=F$$

Tangohia te \frac{mv^{2}}{2} mai i ngā taha e rua.

$$mg=F-\frac{mv^{2}}{2}$$

Whakareatia ngā taha e rua o te whārite ki te 2.

$$2mg=2F-mv^{2}$$

Whakawehea ngā taha e rua ki te 2m.

$$\frac{2mg}{2m}=\frac{2F-mv^{2}}{2m}$$

Mā te whakawehe ki te 2m ka wetekia te whakareanga ki te 2m.

$$g=\frac{2F-mv^{2}}{2m}$$

Whakawehe -mv^{2}+2F ki te 2m.

$$g=-\frac{v^{2}}{2}+\frac{F}{m}$$

Whakaoti mō F

$$F=\frac{m\left(v^{2}+2g\right)}{2}$$