Whakaoti i te F=55*98m/s^2=

$$F = 55 \times 98 m / s ^ { 2 } =$$

Whakaoti mō m

$$m=\frac{Fs^{2}}{5390}$$

$$s\neq 0$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakareatia ngā taha e rua o te whārite ki te s^{2}.

$$Fs^{2}=55\times 98m$$

Whakareatia te 55 ki te 98, ka 5390.

$$Fs^{2}=5390m$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$5390m=Fs^{2}$$

Whakawehea ngā taha e rua ki te 5390.

$$\frac{5390m}{5390}=\frac{Fs^{2}}{5390}$$

Mā te whakawehe ki te 5390 ka wetekia te whakareanga ki te 5390.

$$m=\frac{Fs^{2}}{5390}$$

Whakaoti mō F

$$F=\frac{5390m}{s^{2}}$$

$$s\neq 0$$