Whakaoti i te F=5.5*9.8m/s^2=

$$F = 5.5 \times 9.8 m / s ^ { 2 } =$$

Whakaoti mō m

$$m=\frac{10Fs^{2}}{539}$$

$$s\neq 0$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakareatia ngā taha e rua o te whārite ki te s^{2}.

$$Fs^{2}=5.5\times 9.8m$$

Whakareatia te 5.5 ki te 9.8, ka 53.9.

$$Fs^{2}=53.9m$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$53.9m=Fs^{2}$$

Whakawehea ngā taha e rua o te whārite ki te 53.9, he ōrite ki te whakarea i ngā taha e rua ki te tau huripoki o te hautanga.

$$\frac{53.9m}{53.9}=\frac{Fs^{2}}{53.9}$$

Mā te whakawehe ki te 53.9 ka wetekia te whakareanga ki te 53.9.

$$m=\frac{Fs^{2}}{53.9}$$

Whakawehe Fs^{2} ki te 53.9 mā te whakarea Fs^{2} ki te tau huripoki o 53.9.

$$m=\frac{10Fs^{2}}{539}$$

Whakaoti mō F

$$F=\frac{539m}{10s^{2}}$$

$$s\neq 0$$