Whakaoti i te E(x)=[x^4+2x^3+x^2/(x+1)^2-9]:(3x-9)-x/3

$$E ( x ) = [ \frac { x ^ { 4 } + 2 x ^ { 3 } + x ^ { 2 } } { ( x + 1 ) ^ { 2 } } - 9 ] : ( 3 x - 9 ) - \frac { x } { 3 }$$

Aromātai

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Ngā Hipanga Rongoā Poto

Me whakatauwehe ngā kīanga kāore anō i whakatauwehea i roto o \frac{x^{4}+2x^{3}+x^{2}}{\left(x+1\right)^{2}}.

$$\frac{\frac{x^{2}\left(x+1\right)^{2}}{\left(x+1\right)^{2}}-9}{3x-9}-\frac{x}{3}$$

Me whakakore tahi te \left(x+1\right)^{2} i te taurunga me te tauraro.

$$\frac{x^{2}-9}{3x-9}-\frac{x}{3}$$

Me whakatauwehe ngā kīanga kāore anō i whakatauwehea i roto o \frac{x^{2}-9}{3x-9}.

$$\frac{\left(x-3\right)\left(x+3\right)}{3\left(x-3\right)}-\frac{x}{3}$$

Me whakakore tahi te x-3 i te taurunga me te tauraro.

$$\frac{x+3}{3}-\frac{x}{3}$$

Tā te mea he rite te tauraro o \frac{x+3}{3} me \frac{x}{3}, me tango rāua mā te tango i ō raua taurunga.

$$\frac{x+3-x}{3}$$

Whakakotahitia ngā kupu rite i x+3-x.

$$\frac{3}{3}$$

Whakawehea te 3 ki te 3, kia riro ko 1.

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Tauwehe

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