Whakaoti i te E=3(lambdac+2Deltac)

$$E = 3 ( \lambda c + 2 \Delta c )$$

Whakaoti mō c

$$\left\{\begin{matrix}c=\frac{E}{3\left(2\Delta +\lambda \right)}\text{, }&\lambda \neq -2\Delta \\c\in \mathrm{R}\text{, }&E=0\text{ and }\lambda =-2\Delta \end{matrix}\right.$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tohatoha hei whakarea te 3 ki te \lambda c+2\Delta c.

$$E=3\lambda c+6\Delta c$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$3\lambda c+6\Delta c=E$$

Pahekotia ngā kīanga tau katoa e whai ana i te c.

$$\left(3\lambda +6\Delta \right)c=E$$

He hanga arowhānui tō te whārite.

$$\left(6\Delta +3\lambda \right)c=E$$

Whakawehea ngā taha e rua ki te 3\lambda +6\Delta .

$$\frac{\left(6\Delta +3\lambda \right)c}{6\Delta +3\lambda }=\frac{E}{6\Delta +3\lambda }$$

Mā te whakawehe ki te 3\lambda +6\Delta ka wetekia te whakareanga ki te 3\lambda +6\Delta .

$$c=\frac{E}{6\Delta +3\lambda }$$

Whakawehe E ki te 3\lambda +6\Delta .

$$c=\frac{E}{3\left(2\Delta +\lambda \right)}$$

Whakaoti mō E

$$E=3c\left(2\Delta +\lambda \right)$$