Whakaoti i te D(D-1)+4D=D(D-8)

$$D ( D - 1 ) + 4 D = D ( D - 8 )$$

Whakaoti mō D

$$D=0$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tohatoha hei whakarea te D ki te D-1.

$$D^{2}-D+4D=D\left(D-8\right)$$

Pahekotia te -D me 4D, ka 3D.

$$D^{2}+3D=D\left(D-8\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te D ki te D-8.

$$D^{2}+3D=D^{2}-8D$$

Tangohia te D^{2} mai i ngā taha e rua.

$$D^{2}+3D-D^{2}=-8D$$

Pahekotia te D^{2} me -D^{2}, ka 0.

$$3D=-8D$$

Me tāpiri te 8D ki ngā taha e rua.

$$3D+8D=0$$

Pahekotia te 3D me 8D, ka 11D.

$$11D=0$$

He ōrite te hua o ngā tau e rua ki 0 ina 0 tētahi o rāua te iti rawa. Tātemea kāore te 11 e ōrite ki 0, me ōrite pū te D ki 0.

$$D=0$$