Whakaoti i te D^2=1

$$D ^ { 2 } = 1$$

Whakaoti mō D

$$D=1$$

$$D=-1$$

Ngā Hipanga Whakamahi Rerekētanga o ngā Pūrua

Tangohia te 1 mai i ngā taha e rua.

$$D^{2}-1=0$$

Whakaarohia te D^{2}-1. Tuhia anō te D^{2}-1 hei D^{2}-1^{2}. Ka taea te rerekētanga o ngā pūrua te whakatauwehe mā te ture: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).

$$\left(D-1\right)\left(D+1\right)=0$$

Hei kimi otinga whārite, me whakaoti te D-1=0 me te D+1=0.

$$D=1 D=-1$$

Ngā Upane mā te Kimi Pūtakerua

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$D=1 D=-1$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Tangohia te 1 mai i ngā taha e rua.

$$D^{2}-1=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me -1 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$D=\frac{0±\sqrt{0^{2}-4\left(-1\right)}}{2}$$

Pūrua 0.

$$D=\frac{0±\sqrt{-4\left(-1\right)}}{2}$$

Whakareatia -4 ki te -1.

$$D=\frac{0±\sqrt{4}}{2}$$

Tuhia te pūtakerua o te 4.

$$D=\frac{0±2}{2}$$

Nā, me whakaoti te whārite D=\frac{0±2}{2} ina he tāpiri te ±. Whakawehe 2 ki te 2.

$$D=1$$

Nā, me whakaoti te whārite D=\frac{0±2}{2} ina he tango te ±. Whakawehe -2 ki te 2.

$$D=-1$$

Kua oti te whārite te whakatau.

$$D=1 D=-1$$