Whakaoti i te D=a(1-sinθ)

$$D = a ( 1 - \sin \theta )$$

Whakaoti mō a

$$\left\{\begin{matrix}a=-\frac{D}{\sin(\theta )-1}\text{, }&\nexists n_{1}\in \mathrm{Z}\text{ : }\theta =2\pi n_{1}+\frac{\pi }{2}\\a\in \mathrm{R}\text{, }&D=0\text{ and }\exists n_{1}\in \mathrm{Z}\text{ : }\theta =2\pi n_{1}+\frac{\pi }{2}\end{matrix}\right.$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$a\left(1-\sin(\theta )\right)=D$$

Whakamahia te āhuatanga tohatoha hei whakarea te a ki te 1-\sin(\theta ).

$$a-a\sin(\theta )=D$$

Pahekotia ngā kīanga tau katoa e whai ana i te a.

$$\left(1-\sin(\theta )\right)a=D$$

He hanga arowhānui tō te whārite.

$$\left(-\sin(\theta )+1\right)a=D$$

Whakawehea ngā taha e rua ki te 1-\sin(\theta ).

$$\frac{\left(-\sin(\theta )+1\right)a}{-\sin(\theta )+1}=\frac{D}{-\sin(\theta )+1}$$

Mā te whakawehe ki te 1-\sin(\theta ) ka wetekia te whakareanga ki te 1-\sin(\theta ).

$$a=\frac{D}{-\sin(\theta )+1}$$

Whakaoti mō D

$$D=a\left(-\sin(\theta )+1\right)$$