Whakaoti i te D=-30+5t+5t^2(sI).tgeq0

$$D = - 30 + 5 t + 5 t ^ { 2 } ( s I ) . t \geq 0$$

Whakaoti mō I

$$\left\{\begin{matrix}I=-\frac{5t-D-30}{5st^{2}}\text{, }&s\neq 0\text{ and }t\neq 0\\I\in \mathrm{R}\text{, }&\left(D=-30\text{ and }t=0\right)\text{ or }\left(D=5t-30\text{ and }s=0\right)\end{matrix}\right.$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$-30+5t+5t^{2}sI=D$$

Me tāpiri te 30 ki ngā taha e rua.

$$5t+5t^{2}sI=D+30$$

Tangohia te 5t mai i ngā taha e rua.

$$5t^{2}sI=D+30-5t$$

He hanga arowhānui tō te whārite.

$$5st^{2}I=30+D-5t$$

Whakawehea ngā taha e rua ki te 5t^{2}s.

$$\frac{5st^{2}I}{5st^{2}}=\frac{30+D-5t}{5st^{2}}$$

Mā te whakawehe ki te 5t^{2}s ka wetekia te whakareanga ki te 5t^{2}s.

$$I=\frac{30+D-5t}{5st^{2}}$$

Whakaoti mō D

$$D=5\left(Ist^{2}+t-6\right)$$