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Whakaoti mō D
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Whakaoti mō x (complex solution)
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Whakaoti mō x
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D=\left(4x\right)^{2}-25-\left(27-20x+9x^{2}\right)
Whakaarohia te \left(4x-5\right)\left(4x+5\right). Ka taea te whakareanga te panoni ki te rerekētanga o ngā pūrua mā te ture: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}. Pūrua 5.
D=4^{2}x^{2}-25-\left(27-20x+9x^{2}\right)
Whakarohaina te \left(4x\right)^{2}.
D=16x^{2}-25-\left(27-20x+9x^{2}\right)
Tātaihia te 4 mā te pū o 2, kia riro ko 16.
D=16x^{2}-25-27+20x-9x^{2}
Hei kimi i te tauaro o 27-20x+9x^{2}, kimihia te tauaro o ia taurangi.
D=16x^{2}-52+20x-9x^{2}
Tangohia te 27 i te -25, ka -52.
D=7x^{2}-52+20x
Pahekotia te 16x^{2} me -9x^{2}, ka 7x^{2}.