Whakaoti i te CO=sqrt{(38^2-1440^2)}

$$C O = \sqrt { ( 38 ^ { 2 } - 1440 ^ { 2 } ) }$$

Whakaoti mō C

$$C=\frac{2\sqrt{518039}i}{O}$$

$$O\neq 0$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tātaihia te 38 mā te pū o 2, kia riro ko 1444.

$$CO=\sqrt{1444-1440^{2}}$$

Tātaihia te 1440 mā te pū o 2, kia riro ko 2073600.

$$CO=\sqrt{1444-2073600}$$

Tangohia te 2073600 i te 1444, ka -2072156.

$$CO=\sqrt{-2072156}$$

Tauwehea te -2072156=\left(2i\right)^{2}\times 518039. Tuhia anō te pūtake rua o te hua \sqrt{\left(2i\right)^{2}\times 518039} hei hua o ngā pūtake rua \sqrt{\left(2i\right)^{2}}\sqrt{518039}. Tuhia te pūtakerua o te \left(2i\right)^{2}.

$$CO=2i\sqrt{518039}$$

Whakaraupapatia anō ngā kīanga tau.

$$CO=2\sqrt{518039}i$$

He hanga arowhānui tō te whārite.

$$OC=2\sqrt{518039}i$$

Whakawehea ngā taha e rua ki te O.

$$\frac{OC}{O}=\frac{2\sqrt{518039}i}{O}$$

Mā te whakawehe ki te O ka wetekia te whakareanga ki te O.

$$C=\frac{2\sqrt{518039}i}{O}$$

Whakaoti mō O

$$O=\frac{2\sqrt{518039}i}{C}$$

$$C\neq 0$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tātaihia te 38 mā te pū o 2, kia riro ko 1444.

$$CO=\sqrt{1444-1440^{2}}$$

Tātaihia te 1440 mā te pū o 2, kia riro ko 2073600.

$$CO=\sqrt{1444-2073600}$$

Tangohia te 2073600 i te 1444, ka -2072156.

$$CO=\sqrt{-2072156}$$

Tauwehea te -2072156=\left(2i\right)^{2}\times 518039. Tuhia anō te pūtake rua o te hua \sqrt{\left(2i\right)^{2}\times 518039} hei hua o ngā pūtake rua \sqrt{\left(2i\right)^{2}}\sqrt{518039}. Tuhia te pūtakerua o te \left(2i\right)^{2}.

$$CO=2i\sqrt{518039}$$

Whakaraupapatia anō ngā kīanga tau.

$$CO=2\sqrt{518039}i$$

Whakawehea ngā taha e rua ki te C.

$$\frac{CO}{C}=\frac{2\sqrt{518039}i}{C}$$

Mā te whakawehe ki te C ka wetekia te whakareanga ki te C.

$$O=\frac{2\sqrt{518039}i}{C}$$