Whakaoti i te C=b(1+1/m)

$$C = b ( 1 + \frac { 1 } { m } )$$

Whakaoti mō b

$$\left\{\begin{matrix}b=\frac{Cm}{m+1}\text{, }&m\neq -1\text{ and }m\neq 0\\b\in \mathrm{R}\text{, }&m=-1\text{ and }C=0\end{matrix}\right.$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakareatia ngā taha e rua o te whārite ki te m.

$$Cm=b\left(1+\frac{1}{m}\right)m$$

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Whakareatia 1 ki te \frac{m}{m}.

$$Cm=b\left(\frac{m}{m}+\frac{1}{m}\right)m$$

Tā te mea he rite te tauraro o \frac{m}{m} me \frac{1}{m}, me tāpiri rāua mā te tāpiri i ō raua taurunga.

$$Cm=b\times \frac{m+1}{m}m$$

Tuhia te b\times \frac{m+1}{m} hei hautanga kotahi.

$$Cm=\frac{b\left(m+1\right)}{m}m$$

Tuhia te \frac{b\left(m+1\right)}{m}m hei hautanga kotahi.

$$Cm=\frac{b\left(m+1\right)m}{m}$$

Me whakakore tahi te m i te taurunga me te tauraro.

$$Cm=b\left(m+1\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te b ki te m+1.

$$Cm=bm+b$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$bm+b=Cm$$

Pahekotia ngā kīanga tau katoa e whai ana i te b.

$$\left(m+1\right)b=Cm$$

Whakawehea ngā taha e rua ki te m+1.

$$\frac{\left(m+1\right)b}{m+1}=\frac{Cm}{m+1}$$

Mā te whakawehe ki te m+1 ka wetekia te whakareanga ki te m+1.

$$b=\frac{Cm}{m+1}$$

Whakaoti mō C

$$C=b+\frac{b}{m}$$

$$m\neq 0$$