Whakaoti i te B^2=1

$$B ^ { 2 } = 1$$

Whakaoti mō B

$$B=1$$

$$B=-1$$

Ngā Hipanga Whakamahi Rerekētanga o ngā Pūrua

Tangohia te 1 mai i ngā taha e rua.

$$B^{2}-1=0$$

Whakaarohia te B^{2}-1. Tuhia anō te B^{2}-1 hei B^{2}-1^{2}. Ka taea te rerekētanga o ngā pūrua te whakatauwehe mā te ture: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).

$$\left(B-1\right)\left(B+1\right)=0$$

Hei kimi otinga whārite, me whakaoti te B-1=0 me te B+1=0.

$$B=1 B=-1$$

Ngā Upane mā te Kimi Pūtakerua

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$B=1 B=-1$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Tangohia te 1 mai i ngā taha e rua.

$$B^{2}-1=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me -1 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$B=\frac{0±\sqrt{0^{2}-4\left(-1\right)}}{2}$$

Pūrua 0.

$$B=\frac{0±\sqrt{-4\left(-1\right)}}{2}$$

Whakareatia -4 ki te -1.

$$B=\frac{0±\sqrt{4}}{2}$$

Tuhia te pūtakerua o te 4.

$$B=\frac{0±2}{2}$$

Nā, me whakaoti te whārite B=\frac{0±2}{2} ina he tāpiri te ±. Whakawehe 2 ki te 2.

$$B=1$$

Nā, me whakaoti te whārite B=\frac{0±2}{2} ina he tango te ±. Whakawehe -2 ki te 2.

$$B=-1$$

Kua oti te whārite te whakatau.

$$B=1 B=-1$$