Whakaoti i te B=(1-2*(2^4/5)^-1*2^3/5)^100

$$B = ( 1 - 2 \cdot ( \frac { 2 ^ { 4 } } { 5 } ) ^ { - 1 } \cdot \frac { 2 ^ { 3 } } { 5 } ) ^ { 100 }$$

Whakaoti mō B

$$B=0$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tātaihia te 2 mā te pū o 4, kia riro ko 16.

$$B=\left(1-2\times \left(\frac{16}{5}\right)^{-1}\times \frac{2^{3}}{5}\right)^{100}$$

Tātaihia te \frac{16}{5} mā te pū o -1, kia riro ko \frac{5}{16}.

$$B=\left(1-2\times \frac{5}{16}\times \frac{2^{3}}{5}\right)^{100}$$

Whakareatia te 2 ki te \frac{5}{16}, ka \frac{5}{8}.

$$B=\left(1-\frac{5}{8}\times \frac{2^{3}}{5}\right)^{100}$$

Tātaihia te 2 mā te pū o 3, kia riro ko 8.

$$B=\left(1-\frac{5}{8}\times \frac{8}{5}\right)^{100}$$

Whakareatia te \frac{5}{8} ki te \frac{8}{5}, ka 1.

$$B=\left(1-1\right)^{100}$$

Tangohia te 1 i te 1, ka 0.

$$B=0^{100}$$

Tātaihia te 0 mā te pū o 100, kia riro ko 0.

$$B=0$$

Tautapa B

$$B≔0$$