Whakaoti i te Ax^2+Bx+C=07

$$A { x }^{ 2 } +Bx+C = 07$$

Whakaoti mō A (complex solution)

$$\left\{\begin{matrix}A=-\frac{Bx+C}{x^{2}}\text{, }&x\neq 0\\A\in \mathrm{C}\text{, }&C=0\text{ and }x=0\end{matrix}\right.$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakareatia te 0 ki te 7, ka 0.

$$Ax^{2}+Bx+C=0$$

Tangohia te Bx mai i ngā taha e rua. Ko te tau i tango i te kore ka hua ko tōna korenga.

$$Ax^{2}+C=-Bx$$

Tangohia te C mai i ngā taha e rua.

$$Ax^{2}=-Bx-C$$

He hanga arowhānui tō te whārite.

$$x^{2}A=-Bx-C$$

Whakawehea ngā taha e rua ki te x^{2}.

$$\frac{x^{2}A}{x^{2}}=\frac{-Bx-C}{x^{2}}$$

Mā te whakawehe ki te x^{2} ka wetekia te whakareanga ki te x^{2}.

$$A=\frac{-Bx-C}{x^{2}}$$

Whakawehe -Bx-C ki te x^{2}.

$$A=-\frac{Bx+C}{x^{2}}$$

Whakaoti mō B (complex solution)

$$\left\{\begin{matrix}B=-Ax-\frac{C}{x}\text{, }&x\neq 0\\B\in \mathrm{C}\text{, }&C=0\text{ and }x=0\end{matrix}\right.$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakareatia te 0 ki te 7, ka 0.

$$Ax^{2}+Bx+C=0$$

Tangohia te Ax^{2} mai i ngā taha e rua. Ko te tau i tango i te kore ka hua ko tōna korenga.

$$Bx+C=-Ax^{2}$$

Tangohia te C mai i ngā taha e rua.

$$Bx=-Ax^{2}-C$$

He hanga arowhānui tō te whārite.

$$xB=-Ax^{2}-C$$

Whakawehea ngā taha e rua ki te x.

$$\frac{xB}{x}=\frac{-Ax^{2}-C}{x}$$

Mā te whakawehe ki te x ka wetekia te whakareanga ki te x.

$$B=\frac{-Ax^{2}-C}{x}$$

Whakawehe -Ax^{2}-C ki te x.

$$B=-Ax-\frac{C}{x}$$

Whakaoti mō A

$$\left\{\begin{matrix}A=-\frac{Bx+C}{x^{2}}\text{, }&x\neq 0\\A\in \mathrm{R}\text{, }&C=0\text{ and }x=0\end{matrix}\right.$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakareatia te 0 ki te 7, ka 0.

$$Ax^{2}+Bx+C=0$$

Tangohia te Bx mai i ngā taha e rua. Ko te tau i tango i te kore ka hua ko tōna korenga.

$$Ax^{2}+C=-Bx$$

Tangohia te C mai i ngā taha e rua.

$$Ax^{2}=-Bx-C$$

He hanga arowhānui tō te whārite.

$$x^{2}A=-Bx-C$$

Whakawehea ngā taha e rua ki te x^{2}.

$$\frac{x^{2}A}{x^{2}}=\frac{-Bx-C}{x^{2}}$$

Mā te whakawehe ki te x^{2} ka wetekia te whakareanga ki te x^{2}.

$$A=\frac{-Bx-C}{x^{2}}$$

Whakawehe -Bx-C ki te x^{2}.

$$A=-\frac{Bx+C}{x^{2}}$$

Whakaoti mō B

$$\left\{\begin{matrix}B=-Ax-\frac{C}{x}\text{, }&x\neq 0\\B\in \mathrm{R}\text{, }&C=0\text{ and }x=0\end{matrix}\right.$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakareatia te 0 ki te 7, ka 0.

$$Ax^{2}+Bx+C=0$$

Tangohia te Ax^{2} mai i ngā taha e rua. Ko te tau i tango i te kore ka hua ko tōna korenga.

$$Bx+C=-Ax^{2}$$

Tangohia te C mai i ngā taha e rua.

$$Bx=-Ax^{2}-C$$

He hanga arowhānui tō te whārite.

$$xB=-Ax^{2}-C$$

Whakawehea ngā taha e rua ki te x.

$$\frac{xB}{x}=\frac{-Ax^{2}-C}{x}$$

Mā te whakawehe ki te x ka wetekia te whakareanga ki te x.

$$B=\frac{-Ax^{2}-C}{x}$$

Whakawehe -Ax^{2}-C ki te x.

$$B=-Ax-\frac{C}{x}$$