Whakaoti i te A^2+18^2=60^2

$$A ^ { 2 } + 18 ^ { 2 } = 60 ^ { 2 }$$

Whakaoti mō A

$$A=6\sqrt{91}\approx 57.236352085$$

$$A=-6\sqrt{91}\approx -57.236352085$$

Ngā Upane mā te Kimi Pūtakerua

Tātaihia te 18 mā te pū o 2, kia riro ko 324.

$$A^{2}+324=60^{2}$$

Tātaihia te 60 mā te pū o 2, kia riro ko 3600.

$$A^{2}+324=3600$$

Tangohia te 324 mai i ngā taha e rua.

$$A^{2}=3600-324$$

Tangohia te 324 i te 3600, ka 3276.

$$A^{2}=3276$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$A=6\sqrt{91} A=-6\sqrt{91}$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Tātaihia te 18 mā te pū o 2, kia riro ko 324.

$$A^{2}+324=60^{2}$$

Tātaihia te 60 mā te pū o 2, kia riro ko 3600.

$$A^{2}+324=3600$$

Tangohia te 3600 mai i ngā taha e rua.

$$A^{2}+324-3600=0$$

Tangohia te 3600 i te 324, ka -3276.

$$A^{2}-3276=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me -3276 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$A=\frac{0±\sqrt{0^{2}-4\left(-3276\right)}}{2}$$

Pūrua 0.

$$A=\frac{0±\sqrt{-4\left(-3276\right)}}{2}$$

Whakareatia -4 ki te -3276.

$$A=\frac{0±\sqrt{13104}}{2}$$

Tuhia te pūtakerua o te 13104.

$$A=\frac{0±12\sqrt{91}}{2}$$

Nā, me whakaoti te whārite A=\frac{0±12\sqrt{91}}{2} ina he tāpiri te ±.

$$A=6\sqrt{91}$$

Nā, me whakaoti te whārite A=\frac{0±12\sqrt{91}}{2} ina he tango te ±.

$$A=-6\sqrt{91}$$

Kua oti te whārite te whakatau.

$$A=6\sqrt{91} A=-6\sqrt{91}$$