Whakaoti i te A=2(ab+ac+bc)

$$A = 2 ( a b + a c + b c )$$

Whakaoti mō a (complex solution)

$$\left\{\begin{matrix}a=-\frac{2bc-A}{2\left(b+c\right)}\text{, }&b\neq -c\\a\in \mathrm{C}\text{, }&A=-2b^{2}\text{ and }c=-b\end{matrix}\right.$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tohatoha hei whakarea te 2 ki te ab+ac+bc.

$$A=2ab+2ac+2bc$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$2ab+2ac+2bc=A$$

Tangohia te 2bc mai i ngā taha e rua.

$$2ab+2ac=A-2bc$$

Pahekotia ngā kīanga tau katoa e whai ana i te a.

$$\left(2b+2c\right)a=A-2bc$$

Whakawehea ngā taha e rua ki te 2b+2c.

$$\frac{\left(2b+2c\right)a}{2b+2c}=\frac{A-2bc}{2b+2c}$$

Mā te whakawehe ki te 2b+2c ka wetekia te whakareanga ki te 2b+2c.

$$a=\frac{A-2bc}{2b+2c}$$

Whakawehe A-2cb ki te 2b+2c.

$$a=\frac{A-2bc}{2\left(b+c\right)}$$

Whakaoti mō a

$$\left\{\begin{matrix}a=-\frac{2bc-A}{2\left(b+c\right)}\text{, }&b\neq -c\\a\in \mathrm{R}\text{, }&A=-2b^{2}\text{ and }c=-b\end{matrix}\right.$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tohatoha hei whakarea te 2 ki te ab+ac+bc.

$$A=2ab+2ac+2bc$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$2ab+2ac+2bc=A$$

Tangohia te 2bc mai i ngā taha e rua.

$$2ab+2ac=A-2bc$$

Pahekotia ngā kīanga tau katoa e whai ana i te a.

$$\left(2b+2c\right)a=A-2bc$$

Whakawehea ngā taha e rua ki te 2b+2c.

$$\frac{\left(2b+2c\right)a}{2b+2c}=\frac{A-2bc}{2b+2c}$$

Mā te whakawehe ki te 2b+2c ka wetekia te whakareanga ki te 2b+2c.

$$a=\frac{A-2bc}{2b+2c}$$

Whakawehe A-2cb ki te 2b+2c.

$$a=\frac{A-2bc}{2\left(b+c\right)}$$

Whakaoti mō A

$$A=2\left(ab+ac+bc\right)$$