Whakaoti i te A=(1/5)^-1+(2012+sqrt{2013})^0+81^frac{1{4}}

$$A = ( \frac { 1 } { 5 } ) ^ { - 1 } + ( 2012 + \sqrt { 2013 } ) ^ { 0 } + 81 ^ { \frac { 1 } { 4 } }$$

Whakaoti mō A

$$A=9$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tātaihia te \frac{1}{5} mā te pū o -1, kia riro ko 5.

$$A=5+\left(2012+\sqrt{2013}\right)^{0}+81^{\frac{1}{4}}$$

Tātaihia te 2012+\sqrt{2013} mā te pū o 0, kia riro ko 1.

$$A=5+1+81^{\frac{1}{4}}$$

Tāpirihia te 5 ki te 1, ka 6.

$$A=6+81^{\frac{1}{4}}$$

Tātaihia te 81 mā te pū o \frac{1}{4}, kia riro ko 3.

$$A=6+3$$

Tāpirihia te 6 ki te 3, ka 9.

$$A=9$$

Tautapa A

$$A≔9$$