Whakaoti i te A=sqrt{7-2x}

$$A = \sqrt { 7 - 2 x }$$

Whakaoti mō x

$$x=\frac{7-A^{2}}{2}$$

$$A\geq 0$$

Ngā Upane mō te Whakaoti Whārite Pūtake

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$\sqrt{7-2x}=A$$

Pūruatia ngā taha e rua o te whārite.

$$-2x+7=A^{2}$$

Me tango 7 mai i ngā taha e rua o te whārite.

$$-2x+7-7=A^{2}-7$$

Mā te tango i te 7 i a ia ake anō ka toe ko te 0.

$$-2x=A^{2}-7$$

Whakawehea ngā taha e rua ki te -2.

$$\frac{-2x}{-2}=\frac{A^{2}-7}{-2}$$

Mā te whakawehe ki te -2 ka wetekia te whakareanga ki te -2.

$$x=\frac{A^{2}-7}{-2}$$

Whakawehe A^{2}-7 ki te -2.

$$x=\frac{7-A^{2}}{2}$$

Whakaoti mō x (complex solution)

$$x=\frac{7-A^{2}}{2}$$

$$arg(A)<\pi \text{ or }A=0$$

Whakaoti mō A

$$A=\sqrt{7-2x}$$

$$x\leq \frac{7}{2}$$