Whakaoti i te 9x-7(x+3)+(x+3)^2+x+3quad1=x^2

$$9 x - 7 ( x + 3 ) + ( x + 3 ) ^ { 2 } + x + 3 \quad 1 = x ^ { 2 }$$

Whakaoti mō x

$$x=1$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tohatoha hei whakarea te -7 ki te x+3.

$$9x-7x-21+\left(x+3\right)^{2}+x+3\times 1=x^{2}$$

Pahekotia te 9x me -7x, ka 2x.

$$2x-21+\left(x+3\right)^{2}+x+3\times 1=x^{2}$$

Whakamahia te ture huarua \left(a+b\right)^{2}=a^{2}+2ab+b^{2} hei whakaroha \left(x+3\right)^{2}.

$$2x-21+x^{2}+6x+9+x+3\times 1=x^{2}$$

Pahekotia te 2x me 6x, ka 8x.

$$8x-21+x^{2}+9+x+3\times 1=x^{2}$$

Tāpirihia te -21 ki te 9, ka -12.

$$8x-12+x^{2}+x+3\times 1=x^{2}$$

Pahekotia te 8x me x, ka 9x.

$$9x-12+x^{2}+3\times 1=x^{2}$$

Whakareatia te 3 ki te 1, ka 3.

$$9x-12+x^{2}+3=x^{2}$$

Tāpirihia te -12 ki te 3, ka -9.

$$9x-9+x^{2}=x^{2}$$

Tangohia te x^{2} mai i ngā taha e rua.

$$9x-9+x^{2}-x^{2}=0$$

Pahekotia te x^{2} me -x^{2}, ka 0.

$$9x-9=0$$

Me tāpiri te 9 ki ngā taha e rua. Ko te tau i tāpiria he kore ka hua koia tonu.

$$9x=9$$

Whakawehea ngā taha e rua ki te 9.

$$x=\frac{9}{9}$$

Whakawehea te 9 ki te 9, kia riro ko 1.

$$x=1$$