Whakaoti i te 9x-5x^4+8x^2+4x^4+8-12x-3x

$$9 x - 5 x ^ { 4 } + 8 x ^ { 2 } + 4 x ^ { 4 } + 8 - 12 x - 3 x$$

Aromātai

$$8-6x+8x^{2}-x^{4}$$

Ngā Upane Otinga

Pahekotia te -5x^{4} me 4x^{4}, ka -x^{4}.

$$9x-x^{4}+8x^{2}+8-12x-3x$$

Pahekotia te 9x me -12x, ka -3x.

$$-3x-x^{4}+8x^{2}+8-3x$$

Pahekotia te -3x me -3x, ka -6x.

$$-6x-x^{4}+8x^{2}+8$$

Kimi Pārōnaki e ai ki x

$$-4x^{3}+16x-6$$

Ngā Upane e Whakamahi ana i te Ture Pārōnaki mō te Tapeke

Pahekotia te -5x^{4} me 4x^{4}, ka -x^{4}.

$$\frac{\mathrm{d}}{\mathrm{d}x}(9x-x^{4}+8x^{2}+8-12x-3x)$$

Pahekotia te 9x me -12x, ka -3x.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-3x-x^{4}+8x^{2}+8-3x)$$

Pahekotia te -3x me -3x, ka -6x.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-6x-x^{4}+8x^{2}+8)$$

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

$$-6x^{1-1}+4\left(-1\right)x^{4-1}+2\times 8x^{2-1}$$

Tango 1 mai i 1.

$$-6x^{0}+4\left(-1\right)x^{4-1}+2\times 8x^{2-1}$$

Whakareatia 4 ki te -1.

$$-6x^{0}-4x^{4-1}+2\times 8x^{2-1}$$

Tango 1 mai i 4.

$$-6x^{0}-4x^{3}+2\times 8x^{2-1}$$

Whakareatia 4 ki te -1.

$$-6x^{0}-4x^{3}+16x^{2-1}$$

Tango 1 mai i 2.

$$-6x^{0}-4x^{3}+16x^{1}$$

Mō tētahi kupu t, t^{1}=t.

$$-6x^{0}-4x^{3}+16x$$

Mō tētahi kupu t mahue te 0, t^{0}=1.

$$-6-4x^{3}+16x$$