Whakaoti i te 9x-(5x+1)-{2+8x-(7x-5)}+9x=0

$$9 x - ( 5 x + 1 ) - \{ 2 + 8 x - ( 7 x - 5 ) \} + 9 x = 0$$

Whakaoti mō x

$$x=\frac{2}{3}\approx 0.666666667$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Hei kimi i te tauaro o 5x+1, kimihia te tauaro o ia taurangi.

$$9x-5x-1-\left(2+8x-\left(7x-5\right)\right)+9x=0$$

Pahekotia te 9x me -5x, ka 4x.

$$4x-1-\left(2+8x-\left(7x-5\right)\right)+9x=0$$

Hei kimi i te tauaro o 7x-5, kimihia te tauaro o ia taurangi.

$$4x-1-\left(2+8x-7x-\left(-5\right)\right)+9x=0$$

Ko te tauaro o -5 ko 5.

$$4x-1-\left(2+8x-7x+5\right)+9x=0$$

Pahekotia te 8x me -7x, ka x.

$$4x-1-\left(2+x+5\right)+9x=0$$

Tāpirihia te 2 ki te 5, ka 7.

$$4x-1-\left(7+x\right)+9x=0$$

Hei kimi i te tauaro o 7+x, kimihia te tauaro o ia taurangi.

$$4x-1-7-x+9x=0$$

Tangohia te 7 i te -1, ka -8.

$$4x-8-x+9x=0$$

Pahekotia te 4x me -x, ka 3x.

$$3x-8+9x=0$$

Pahekotia te 3x me 9x, ka 12x.

$$12x-8=0$$

Me tāpiri te 8 ki ngā taha e rua. Ko te tau i tāpiria he kore ka hua koia tonu.

$$12x=8$$

Whakawehea ngā taha e rua ki te 12.

$$x=\frac{8}{12}$$

Whakahekea te hautanga \frac{8}{12} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 4.

$$x=\frac{2}{3}$$